Chem 1 Study guides, Class notes & Summaries

CHEM 120 Week 5 Exam 2 (Units 3 and 4)

Station 1. You have run an experiment studying the effects of the molecular weight of a compound on the rate of diffusion in agar. Compound X has a molecular weight of 25.3 g/mol and compound Y has a molecular mass of 156.2 g/mol. On two separate agar plates, 0.1 g of each substance were transferred and allowed to diffuse for 2 hours. The results below were obtained. Use this information about this situation to answer the following three questions. 1. Question: (CO 1) What was the independent v...

CHEM 103 Module 3 Exam Portage Learning 2023. NH4Cl is being dissolved in water and this process is being studied in a styrofoam coffee cup with a lid and the heat absorbed is measured by means of a thermometer immersed in the reaction mixture. Enter the correct thermochemistry term to describe the item listed. 1. The type of thermochemical process 2. The air above the cup Your Answer: 1) endothermic 2) Surroundings 1. Heat absorbed = Endothermic process 2. The air above the cup = Surro...

CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. Using the following info...

Portage Learning - CHEM 103 MODULE 5 Exam

1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. Your Answer: 1.) Convert 1005.3 to exponential form and explain your answer: All number values must be between 1-10. Because this value is greater than 1, the exponent remains positive. In order for this to happen, we have to move the decimal three places to the LEFT thus, the exponential form of 1005.3 is: 1.0053 X 103

CHEM 219 EXAM 1 ALL QUESTIONS WITH COMPLETE SOLUTION.